SOLUTION: The path of the diver is given by y= 4/9 x^2 +24/9 x+12 where y is the height in feet and x is the horizontal distance from the end of the diving board (in feet). What is the maxim, 2/13/2013 · Where y is the height (in feet) and x I the horizontal distance from the end of the diving board (in feet). What is the maximum height of the driver ?, ?? Correct answer to the question The path of a driver is given by y=- 4/9x^2 +24x/9+ 12 where x is horizontal distance in feet and y is the vertical distance. in feet. from what height does the diver jump? what is the maximum height of the dive? – e-eduanswers.com, 9/28/2015 · The path of a diver is given by y=-4/9 x^2 + 24/9x +12 where y is the height (in feet) and x is the horizontal distance from the end of the diving board.
4/30/2015 · The vertex of the parabola y = ax² + bx + c occurs at x=-b/2a. With a=-4/9 and b=24/9, the x coordinate of the vertex is: x = -b/ (2a) = (-24/9) / (-8/9) = 24/8 = 3. y = – (4/9)x² + (24/9)x + 12 = (-4/9) (9) + (24/9) (3) + 12 . y = -4 + 8 + 12 = 16. The maximum height is 16 ft. …Show more.
10/20/2017 · the path of a diver is y= – 4/9x^2 + 24/9x + 12 . Where y is the height (in feet) and x is the horizontal distance (in feet) from the end of the diving board.
Maximum Height of a Diver The path of a diver is given by y = – 4/9 x^2 + 24/9 x +10 where y is the height (in feet) and x is the horizontal distance from the end of the diving board (in feet) (see figure). Use a graphing utility and the trace or maximum feature to find the maximum height of the diver.
The path of a basketball thrown at an angle of 45° can be modeled by y = -0.02x 2 + x + 6. Answer: Question 36. The path of a shot put released at an angle of 35° can be modeled by y = -0.01x 2 + 0.7x + 6. Answer: Question 37. ANALYZING EQUATIONS The graph of which function has the same axis of symmetry as the graph of y = x 2 + 2x + 2? A. y …
Q: The path of a diver is modeled by f(x)= -4/9×2 + 24/9x + 9 where f(x) is the height (in feet) and x … A: Since, we have been given the path of driver by :-f(X)=Y=-49X2+ 249X +9 -(i)Our aim is to find the ma…
